Question

Write down the rationalizing factors of the following irrational numbers. a. 2√3 b. -5√7 c. √3+√5 d. 2√6-√7 e. 3√10+2√5

Answer 1

Answer:

Here goes the SOLUTION

Step-by-step explanation:

Rationalizing factors of

a)

$2 \sqrt{3 } = 1$

b)

$- 5 \sqrt{7 } = 1$

c)

$\sqrt{3 } + \sqrt{5} = \sqrt{3} - \sqrt{5}$

d)

$2 \sqrt{6} - \sqrt{7} = 2 \sqrt{6} + \sqrt{7}$

e)

$3 \sqrt{10} + 2\sqrt{5} = 3 \sqrt{10} - 2\sqrt{5}$

Enjoy Maths!!

(SK STUDY POINT SILIGURI)

Answer 2

Answer:

$a)2 \sqrt{3 = 1}$

$b) - 5 \sqrt{7} = 1$

$c) \sqrt{3} + \sqrt{5} = \sqrt{3} - \sqrt{5}$