write down the slope for 3x+4y-2(x+X1)-5(y+y1)+2=0
Answers
Answer
The given lines are perpendicular and as AB = AC , Therefore △ ABC is art . angled isosceles . Hence the line BC through ( 1 , 2) will make an angles of ±45
∘
with the given lines . Its equations is y - 2 = m (x - 1) where m = 1 / 7 and -7 as in .Hence the possible equations are 7x + y - 9 = 0 and x - 7y + 13 = 0
Alt :
The two lines will be parallel to bisectors of angle between given lines and they pass through ( 1, 2)
∴ y - 2 = m ( x - 1)
where m is slope of any of bisectors given by
5
3x+4y−5
=±
5
4x−3y−15
or x - 7y + 13 = 0 or 7x + y - 20 = 0
∴ m = 1 / 7 or - 7
putting in (1) , the required lines are 7x + y - 9 = 0
and x - 7y + 13 = 0 as found above
Answer:
3x+4y-(2x+2x)-(5y+5y)+2=0
3x+4y-2x-2x-5y-5y+2=0
3x-2x-2x+2=5y+5y-4y
3x-4x+2=10y-4y
x+2=6y
6y=x+2
6y-x=2