write down the smallest digit in unit place so that the number is divisible by the digit written at the top
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Sum of the remaining digits=24
To make the number divisible by 3, the sum of its digits should be divisible by 3. As 24 is already divisible by 3, the smallest number that can be placed here is 0.
Now, 0+3=3
3+3=6
3+3+3=9
How ever, 3+3+3+3=12
If we put 9, then the sum of the digits will be 33 and as 33 is divisible by 3, the number will also be divisible by 3.
Therefore, the largest number is 9.
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