Question

Write down the various method for the preparation of $N_2$. {relevant to JEE ADVANCE}​

Answer 1

$\orange{\underline{Dinitrogen}}$

• Dinitrogen is an inert gas due to its high bond dissociation energy.

• Its bond order is three.It is a diatomic gas having three bonds between two nitrogen atoms.

Preparation

$\green{\textsf{Various methods for the preparation of N_2\: are }}$

(i) $NH_4NO_2\: \overset{\Delta}{\longrightarrow} N_2\:+\:H_20$

(ii) By heating Ammonium dichromate :-

${(NH_4)}_2Cr_2O_7\: \overset{\Delta}{\longrightarrow} N_2\:+\:4H_2O\: +Cr_2O_3$

(iii)

$\green{Purest \:method \:for \:the \:preparation\: of \:N_2 \: are } :- \\ Ba{(N_3)}_2\: \overset{\Delta} {\longrightarrow} \: Ba\:+\:3N_2 \\ \\ 2NaN_3 \: \overset{\Delta} {\longrightarrow} \: 2Na\:+\:3N_2$

Additional Details :-

Preparation of $N_2$ in the laboratory :-

$NH_4Cl\:+NaNO_2 \longrightarrow\: N_2\:+\:2H_20\:+\:NaCl$

Answer 2

Answer:

Dinitrogen

$</p><p>Dinitrogen</p><p></p><p>Dinitrogen is an inert gas due to its high bond dissociation energy.</p><p></p><p>Its bond order is three.It is a diatomic gas having three bonds between two nitrogen atoms.</p><p></p><p>$

Dinitrogen is an inert gas due to its high bond dissociation energy.

Its bond order is three.It is a diatomic gas having three bonds between two nitrogen atoms.