Question

write down thr dimensions of each of the following in terms of mass, length , time and charge a ) magnetic flux (b) modulus of rigidity​

Answer 1

Answer:

if it is help full mark as brilliant

Explanation:

a)(a) magnetic flux , ϕ=Bs=[F][qv](s)

∴[ϕ]=[Fsqv]=[MLT−2L−2QLT−1]

=[ML2T−1Q−1]

(b) [kindly Modulus] = (FA]=(MLT−1L2]

=[ML−1T−2]

Answer 2

$\sf{\purple{\underline{\underline{\red{\huge{Answer:-}}}}}}$

1) The Dimension Of “Magnetic Flux” :-

$\tt{\green{\boxed{Magnetic\:Flux\:=\:Magnetic\:field\:\times\:Area\:}}}$

$\tt{\pink{\implies\:Magnetic\:Flux\:=\:[M^1\:T^{-2}\:A^{-1}][L^2]\:}}$

$\bigstar\:\tt{\red{\boxed{\implies\:Magnetic\:Flux\:=\:[M^1\:L^2\:T^{-2}\:A^{-1}]\:}}}$

$\bigstar\:\tt{\green{\boxed{\implies\:Magnetic\:Flux\:=\:[M^1\:L^2\:T^{-1}\:Q^{-1}]}}}$

2) The Dimension Of “Modulus Of Rigidity” :-

$\tt{\purple{\boxed{\:Modulus\:Of\:Rigidity\:=\:{\dfrac{shear\:stress}{shear\:strain}}\:}}}$

$\tt{\blue{\implies\:Modulus\:Of\:Rigidity\:=\:{\dfrac{[M^1\:L^{-1}\:T^{-2}]}{[M^0\:L^0\:T^0]}}\:}}$

$\bigstar\:\tt{\orange{\boxed{\implies\:Modulus\:Of\:Rigidity\:=\:[M^1\:L^{-1}\:T^{-2}]\:}}}$