Question

Write down two pairs of integers whose
(i) Sum is –4
(ii) Difference is –2
(iii) Sum is –5
(iv) Sum is 0​

Answer 1

Answer:

hint....

We will fix one integer in every of the given options and then assume another integer to be any one of the variables like a or b. Then, we will put in the values as per given conditions and find the number which the variable takes and thus we have a pair of integers.

Step-by-step explanation:

Complete step-by-step answer:

Let us solve the first option first of all.

Option A: sum is -3

Let us fix one integer to be 1. Now, let another integer be a.

Now, we have the sum of these both integers to be equal to -3.

⇒1+a=−3⇒1+a=−3

Now, taking 1 from addition in LHS to subtraction in RHS, we will get:-

⇒a=−3−1=−4⇒a=−3−1=−4

Thus, we have our two integers 1 and -4.

∴∴ The required pair of integers whose sum will be -3 is 1 and -4.

Option B: difference is -5

Let us fix one integer to be 1. Now, let another integer be b.

Now, we have the difference of these both integers to be equal to -5.

⇒1−b=−5⇒1−b=−5

Now, taking 1 from addition in LHS to subtraction in RHS, we will get:-

⇒−b=−5−1=−6⇒−b=−5−1=−6

⇒b=6⇒b=6

Thus, we have our two integers 1 and 6.

∴∴ The required pair of integers whose difference will be -5 is 1 and 6 respectively.

Option C: difference is 2

Let us fix one integer to be 1. Now, let another integer be c.

Now, we have the difference of these both integers to be equal to 2.

⇒1−c=2⇒1−c=2

Now, taking 1 from addition in LHS to subtraction in RHS, we will get:-

⇒−c=2−1=1⇒−c=2−1=1

⇒c=−1⇒c=−1

Thus, we have our two integers 1 and -1.

∴∴ The required pair of integers whose difference will be 2 is 1 and -1 respectively.

Option D: sum is 0

Let us fix one integer to be 1. Now, let another integer be d.

Now, we have the sum of these both integers to be equal to 0.

⇒1+d=0⇒1+d=0

Now, taking 1 from addition in LHS to subtraction in RHS, we will get:-

⇒d=−1⇒d=−1

Thus, we have our two integers 1 and -1.

∴∴ The required pair of integers whose sum will be 0 is 1 and -1.

*plz follow and msrk me brainlist*

Note: The students must note that they can fix any number (not necessarily equal to 1) for the calculations. But they must be aware of 0 for the fourth part because a sum of two numbers among which one is 0 is only possible if the other number is 0 as well. So, then both the numbers will be 0 and it would not be distinct digits (if required distinct digits).

We can here do this using fixing numbers because Integers are closed under addition and subtraction.