Question

Write down unit and dimension of permittivity of free space.
Permittivity of force​

Answer 1

Answer:

ok

thank you

Explanation:

You can see that the formula for permittivity and permittivity of free space is the same. So, the unit of permittivity of free space = A2s4Kg−1m−3 = Fm−1. Having the same formula as permittivity, the dimension of permittivity of vacuum is also [M−1A2T4L−3]

Answer 2

Permittivity of force space ε0 appears in coulombs law

F = 1/4πε0 * (q1q2)/r²

Unit :-

N = 1/[ε0]unit * (C*C)/m²

[ε0] unit = C²N^-1m^-2

Dimensions :-

[MLT^-2] = 1/[ε0] * (AT*AT)/L²

[ε0] = [M^-1L^-1T²A²T²L^-2]

= [M^-1L^-3T⁴A²]