Math, asked by aryanmiriyala89, 10 months ago

Write each of the following numbers as difference of the square of two consecutive natural numbers. (i) 49 (ii) 75 (iii) 125

Answers

Answered by harikairuvuru
86

Answer:

i)24 and 25 ii)37 and 38 iii)62 and 63

Step-by-step explanation:

Let one Natural number be x

Another natural number=x+1

i)Difference of their squares=49

(x+1)²-x²=49

x²+2x+1-x²=49

2x=48

x=24

Two consecutive Numbers are 24 and 25.

ii)Difference of their squares =75

(x+1)²-x²=75

x²+2x+1-x²=75

2x=74

x=37

The consecutive numbers are 37 and 38

iii)Difference of their squares =125

(x+1)²-x²=125

x²+2x+1-x²=125

2x=124

x=62

The consecutive numbers are 62 and 63

Answered by jagnaniyashika
19

Answer:

i)24 and 25 ii)37 and 38 iii)62 and 63

Step-by-step explanation:

Let one Natural number be x

Another natural number=x+1

i)Difference of their squares=49

(x+1)²-x²=49

x²+2x+1-x²=49

2x=48

x=24

Two consecutive Numbers are 24 and 25.

ii)Difference of their squares =75

(x+1)²-x²=75

x²+2x+1-x²=75

2x=74

x=37

The consecutive numbers are 37 and 38

iii)Difference of their squares =125

(x+1)²-x²=125

x²+2x+1-x²=125

2x=124

x=62

The consecutive numbers are 62 and 63

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