Question

Write each of the following statements by using appropriate grouping
symbols:
(i) The sum of a – b and 3a – 2b + 5 is subtracted from 4a + 2b – 7.
(ii) Three times the sum of 2x + y – [5 – (x – 3y)] and 7x – 4y + 3 is subtracted
from 3x – 4y + 7
(iii) The subtraction of x2 – y
2 + 4xy from 2x2 + y2 – 3xy is added to 9x2 – 3y2–
xy.

Answer 1

Answer:

Solution:

(i) The sum of a – b and 3a – 2b + 5 = [(a – b) + (3a – 2b + 5)].

This is subtracted from 4a + 2b – 7.

Thus, the required expression is (4a + 2b – 7) – [(a – b) + (3a – 2b + 5)]

(ii) Three times the sum of 2x + y – {5 – (x – 3y)} and 7x – 4y + 3 = 3[(2x + y – {5 – (x – 3y)}) + (7x – 4y + 3)]

This is subtracted from 3x – 4y + 7.

Thus, the required expression is (3x – 4y + 7) – 3[(2x + y – {5 – (x – 3y)}) + (7x – 4y + 3)]

(iii) The product of subtraction of x2- y2 + 4xy from 2x2 + y2 - 3xy is given by {(2x2 + y2 - 3xy) – (x2-y2 + 4xy)}

When the above equation is added to 9x2 - 3y2 - xy, we get

{(2x2 + y2 - 3xy) – (x2 - y2 + 4xy)} + (9x2 - 3y2- xy))