Write electron configuration for the following ions: (i) Fe3+ (ii) Cr3+ (iii) Pb2+ (iv) Pb 4+ (v) O2
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3
K L M N O P Q R
Fe3+. 2,8,13
Cr3+. 2,8,11
Pb2+. 2,8,18,32,18,2
Pb4+. 2,8,18,32,18
O2-. 2,8
Fe3+. 2,8,13
Cr3+. 2,8,11
Pb2+. 2,8,18,32,18,2
Pb4+. 2,8,18,32,18
O2-. 2,8
Answered by
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Fe3+=1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^3
Cr3+= 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^1
Pb2+= 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^14 5d^10
Pb4+= 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^14 5d^8
O2-=1s^2 2s^2 2p^2
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Cr3+= 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^1
Pb2+= 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^14 5d^10
Pb4+= 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^14 5d^8
O2-=1s^2 2s^2 2p^2
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