Chemistry, asked by karthik655699, 7 months ago

Write electron configuration from na to ca​

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Answered by Anonymous
2

\underline\mathfrak{answer}

Na: atomic number 11

 {1s}^{2}  {2s}^{2}  {2p}^{6}  {3s}^{2} Mg:12

\begin{gathered}1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} \\ Al:13 = 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} \: 3 {p}^{1} \\ Si:14 = \: 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} \: 3 {p}^{2} \\ P:15 = 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} \: 3 {p}^{3} \\ S:16 = 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} \: 3 {p}^{4} \\ Cl:17 = 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} \: 3 {p}^{5} \\ Ar :18= 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} \: 3 {p}^{6} \\ K:19 = 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} \: 3 {p}^{6}4 {s}^{1} \\ Ca:20 = 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} \: 3 {p}^{6} \: 4 {s}^{1}\end{gathered}

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