Write electronic configration of an element whose atomic no. is (A) 5 (b) 6 (c) 8 (d) 10 (e) 11 (f) 12
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Answers
Explanation:
As we know, atomic number is the total no of proton present in nucleus of an atom and atomic mass number is the total no of proton and neutron.
So boron have atomic number 5 and mass number 5+6=11. Therefore, K shell will accommodate 2 electrons and L shell will accommodate remaining electrons i.e 3. The electronic configuration is 2, 3.
Answer:
2 He Helium 4.00260
3 Li Lithium 6.941
4 Be Beryllium 9.01218
5 B Boron 10.81
6 C Carbon 12.011
7 N Nitrogen 14.0067
8 O Oxygen 15.9994
9 F Fluorine 18.998403
10 Ne Neon 20.179
11 Na Sodium 22.98977
12 Mg Magnesium 24.305
13 Al Aluminum 26.98154
14 Si Silicon 28.0855
15 P Phosphorus 30.97376
16 S Sulfur 32.06
17 Cl Chlorine 35.453
18 Ar Argon 39.948
19 K Potassium 39.0983
20 Ca Calcium 40.08
21 Sc Scandium 44.9559
22 Ti Titanium 47.90
23 V Vanadium 50.9415
24 Cr Chromium 51.996
25 Mn Manganese 54.9380
26 Fe Iron 55.847
27 Co Cobalt 58.9332
28 Ni Nickel 58.70
29 Cu Copper 63.546
30 Zn Zinc 65.38
31 Ga Gallium 69.72
32 Ge Germanium 72.59
33 As Arsenic 74.9216
34 Se Selenium 78.96
35 Br Bromine 79.904
36 Kr Krypton 83.80
37 Rb Rubidium 85.4678
38 Sr Strontium 87.62
39 Y Yttrium 88.9059
40 Zr Zirconium 91.22
41 Nb Niobium 92.9064
42 Mo Molybdenum 95.94
43 Tc Technetium (98)
44 Ru Ruthenium 101.07
45 Rh Rhodium 102.9055
46 Pd Palladium 106.4
47 Ag Silver 107.868
48 Cd Cadmium 112.41
49 In Indium 114.82
Explanation:
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