Chemistry, asked by Anonymous, 5 months ago

write energy level diagram of Ne2​

Answers

Answered by Legend42
3

Answer:

Formation of N

2

molecule: Electronic Configuration,

σ1s

2

<σ∗1s

2

<σ2s

2

<σ∗2s

2

<[π2p

x

2

=π2p

x

2

]<<σ2p

z

2

Bond order = (N

b

−N

a

)/2=(10−4)/2=3

Bond order indicates the number of bonds in diatomic molecule is 3, hence TripleBond

Formation of F

2

molecule: Electronic Configuration:

σ1s

2

<σ∗1s

2

<σ2s

2

<σ∗2s

z

2

σ∗2pz

2

<[π2p

x

2

=π2p

x

2

]<[π∗2p

x

2

=π∗2p

x

2

]<σ2p

z

Bond order = (N

b

−N

a

)/2=(10−8)/2=1

Single bond F−F.

Formation of Ne

2

molecule: Electronic Configuration,

σ1s

2

<σ∗1s

2

<σ2s

2

<σ∗2s

z

2

<σ∗2pz

2

<[π2p

x

2

=π2p

x

2

]<[π∗2p

x

2

=π∗2p

x

2

]<σ2p

z

2

Bond order = (N

b

−N

a

)/2=(10−10)/2=0

Hence, no bond between Ne atoms.

Answered by itzOPgamer
0

Answer:

Molecular orbital diagram of

Explanation:

  • Neon atom has 10 electrons and its electronic configuration is . When  molecule is considered, it has two neon atoms and thus is composed of 20 electrons.

  • As the bond order value for  molecule is zero, it is unstable and cannot exist.
  • The molecular orbital diagram of hypothetical  molecule is given in the attachment.

Learn more about such concept

Draw the molecular orbital diagram of N2 and calculate the bond order

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