Question

write equation 2y = 10-y^2
in the ax^2 + bx + c =0

form.
→​

Answer 1

Answer:

$1.y^{2} + (-2y) + 10 = 0$

Step-by-step explanation:

$2y= 10 - y^{2}$

$or, 10 - y^{2} - 2y = 0$

$1.y^{2} + (-2y) + 10 = 0$

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Answer 2

Question :

Write the equation 2y = 10-y² in ax²+bx+c=0 form

Answer:

a= 1 b= 2 c= -10

Step-by-step explanation:

2y=10-y²

⇒y²+2y-10=0

On comparing  from the standard form of quadratic equation ax²+bx+c=0

y²+2y-10=0

Where a= 1 b= 2 c= -10