Question

write equation in the form ax+by+c=0 in case 3x=2​

Answer 1

Answer:

(i) 2x+3y=9.3

5

ˉ

⇒2x+3y−9.3

5

ˉ

Comparing the equation with ax+by+c=0

a=2,b=3,c=−9.3

5

ˉ

(ii) x−

5

y

−10=0

Comparing the equation with ax+by+c=0

a=1,b=−

5

1

,c=−10

(iii) −2x+3y=6

⇒−2x+3y−6=0

Comparing the equation with ax+by+c=0

a=−2,b=3,c=−6

(iv) x=3y

⇒x−3y=0

Comparing the equation with ax+by+c=0

a=1,b=−3,c=0

(v) 2x=−5y

⇒2x+5y=0

Comparing the equation with ax+by+c=0

a=2,b=5,c=0

(vi) 3x+2=0

⇒3x+0y+2=0

Comparing the equation with ax+by+c=0

a=3,b=0,c=2

(vii) y−2=0

⇒0x+y−2=0

Comparing the equation with ax+by+c=0

a=0,b=1,c=−2

(viii) 5=2x

⇒−2x+0y+5

Comparing the equation with ax+by+c=0

a=−2,b=0,c=5

Step-by-step explanation:

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Answer 2

Given 3x=2
So,
3x-2=0
3x-2y+0=0
In the case 3x=2,equation in the form of ax+by+c=0 is 3x-2y+0=0