Question

Write equations for the reaction of diborane with (i) H2O (ii) NH3 and (iii) CO​

Answer 1

Answer:

(i) B2H6 + 6H2O — 2 B(OH)3 + 6H2.

(ii) 3B2H6 + 6NH3 — 2B3N3H6 + 12H2

(iii) 2CO + B2H6 — 2BH3CO

*The horizontal line in the middle is supposed to be an arrow and it is regularly an arrow when you are writing equations*

Explanation:

(i) When Diborane reacts with water (H2O) it produces hydrogen and boric acid.

(ii) When Diborane reacts with ammonia (NH3) it produces a borazine and hydrogen.

(iii) When Diborane reacts with carbon monoxide (CO) it produces a borane carbonyl.

Answer 2

Answer:

(i) B2H6 + 6H2O — 2 B(OH)3 + 6H2.

(ii) 3B2H6 + 6NH3 — 2B3N3H6 + 12H2

(iii) 2CO + B2H6 — 2BH3CO

Explanation:

Step 1: The horizontal line in the middle is supposed to be an arrow and it is regularly an arrow when you are writing equations

Step 2: (i) Hydrogen and boric acid are produced when diborane and water (H2O) combine.

Step 3: (ii) Borazine and hydrogen are created when diborane and ammonia (NH3) combine.

Step 4: (iii) A borane carbonyl is created when diborane and carbon monoxide (CO) combine.

(i) B2H6 + 6H2O — 2 B(OH)3 + 6H2.

(ii) 3B2H6 + 6NH3 — 2B3N3H6 + 12H2

(iii) 2CO + B2H6 — 2BH3CO

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