Question

write expression as a single function sin^2 142°/1+cos 142°​

Answer 1

SOLUTION

TO DETERMINE

The expression as a single function

$\displaystyle \sf{ \frac{ { \sin}^{2} {142}^{ \circ} }{1 + \cos {142}^{ \circ}} }$

FORMULA TO BE IMPLEMENTED

We are aware of the Trigonometric formula that

sin² θ = 1 - cos² θ

EVALUATION

$\displaystyle \sf{ \frac{ { \sin}^{2} {142}^{ \circ} }{1 + \cos {142}^{ \circ}} }$

$\displaystyle \sf{ = \frac{ 1 - { \cos}^{2} {142}^{ \circ} }{1 + \cos {142}^{ \circ}} }$

$\displaystyle \sf{ = \frac{ {1}^{2} - { \cos}^{2} {142}^{ \circ} }{1 + \cos {142}^{ \circ}} }$

$\displaystyle \sf{ = \frac{(1 + \cos {142}^{ \circ})(1 - \cos {142}^{ \circ})}{1 + \cos {142}^{ \circ}} }$

$\displaystyle \sf{ = 1 - \cos {142}^{ \circ}}$

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Answer 2

Answer:

Step-by-step explanation:

1.You can make  first + to 4 by using  Straight line  

2. After that you can see 141+1=142

That's all  Easy answer