Write expression for Kinetic Energy.A force of 12N acts on an
object of mass of 4kg in the state of rest for 3s. Calculate the kinetic energy acquired by the object
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Answer:
For a block in equilibrium,
Equating forces along Y−axis,
Normal reaction, N=mg
Equating forces along X−axis,
ma=F−f
where f=μmg
ma=F−μmg
a=
m
F−μmg
a=
4
12−0.2×4×10
a=
4
12−8
a=
4
4
a=1 ms
−2
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