Question

write factors of the polynomial 12x square -x - 6

Answer 1

Hey!!
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Here is your answer!!
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12x^2-x-6
12x^2-(9-8)x-6
12x^2-9x+8x-6
3x(4x-3)+2(4x-6)
(4x-3)(3x+2)
4x-3=0 or 3x+2=0
x=3/4 x=-2/3
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I hope it will help you!!!

Answer 2

Answer: (3x+2) and (4x-3)

Step-by-step explanation:

• Given, polynomial $12x^{2} -x-6=0$.
• To factorize the given polynomial we need to compare it with the standard equation of polynomial.
• The standard equation of polynomial is $ax^{2} +bx+c=0$.
• To factorize a polynomial the product of the coefficient of $x^{2}$ and c is written such that on adding the factors of the product we get the co-efficient of x.
• Now according to question,

          $12x^{2} -x-6=0$

      ⇒ $12x^{2}$ - 9x + 8x - 6 = 0

      ⇒ 3x(4x-3) +2(4x-3)=0

      ⇒ (3x+2)(4x-3)=0

• So, the required factors of the given polynomial is (3x+2) and (4x-3).

• Hence, the required answer is (3x+2) and (4x-3).

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