Question

..Write factors of the polynomial
$12 {x}^{2} - x - 6$
​

Answer 1

Step-by-step explanation:

$12x {}^{2} - x - 6 = 12x {}^{2} - 9x + 8x - 6 \\ \\ = 3x(4x - 3) + 2(4x - 3) = \\ \\ =( 3x + 2)(4x - 3)$

so 3x+2 = 0 & 4x-3= 0

x=-2/3 & x=3/4

so the answer is x= 3/4

Answer 2

Step-by-step explanation:

\begin{gathered}12x {}^{2} - x - 6 = 12x {}^{2} - 9x + 8x - 6 \\ \\ = 3x(4x - 3) + 2(4x - 3) = \\ \\ =( 3x + 2)(4x - 3)\end{gathered}12x2−x−6=12x2−9x+8x−6=3x(4x−3)+2(4x−3)==(3x+2)(4x−3)

so 3x+2 = 0 & 4x-3= 0

x=-2/3 & x=3/4

so the answer is x= 3/4

hope it helps!!

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