Question

Write Faraday's laws of electrolysis.

Page 87 Chapter - 4.Electricity

Answer 1

first law
w proposnal to q
w=kq
w=kit
2 law
w1/w2=z1/z2

Answer 2

Faraday's laws can be summarized by

{\displaystyle m\ =\ \left({Q \over F}\right)\left({M \over z}\right)}

where:

m is the mass of the substance liberated at an electrode in gramsQ is the total electric charge passed through the substance in coulombsF = 96485 C mol−1 is the Faraday constantM is the molar mass of the substance in grams per molz is the valency number of ions of the substance (electrons transferred per ion).

Note that M/z is the same as the equivalent weight of the substance altered.

For Faraday's first law, M, F, and z are constants, so that the larger the value of Qthe larger m will be.

For Faraday's second law, Q, F, and z are constants, so that the larger the value of M/z (equivalent weight) the larger m will be.

In the simple case of constant-current electrolysis, {\displaystyle Q=It} leading to

{\displaystyle m\ =\ \left({It \over F}\right)\left({M \over z}\right)}