write first 3 terms of arithmetic sequence a. first term is 60 ;the sum of first 3term is 600 b. first term is 60 the sum of first 4 term is 300
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Step-by-step explanation:
The three terms are 30,100,170
The first term a is given by 30 , let the common difference be d
Sum of first three terms =300
Sum of n terms of an AP is given by (n÷2)×(2a+(n-1)×d)
In this case n=3 and a=30
(3÷2)×(60+2d)=300
60+2d=200
2d=140
d=70
The second term is 30+70=100
The third term is 100+70=170
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