Question

Write first 7 terms of an=3n2 + 2n - 6​

Answer 1

Answer:

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Your required answer :

Given = 3n2 +2n - 6

• a1 = ( 3 × 1 ) + 2 = 3 + 2 = 5
• a2 = (3 × 2 ) + 2 = 6 + 2 = 8
• a3 = ( 3 × 3 ) + 2 = 9 + 2 = 11
• a4 = ( 3 × 4 ) + 2 = 12 + 2 = 14
• a5 = ( 3 × 5 ) + 2 = 15 + 2 = 17
• a6 = ( 3 × 6 ) + 2 = 18 + 2 = 20
• a7 = ( 3 × 7 ) + 2 = 21 + 2 = 23

Therefore the given A.P. will be :

5 , 8 ,11 ,14 ,17 ,20 and 23

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