Math, asked by prithvboxer77, 10 months ago

Write first four terms of the AP, when the first term a and the common difference d are
given as follows
(iii) a = 4, d = – 3

Answers

Answered by Vishal101100

$\huge\pink{\underline{GOOD-MORNING}}$

$<body bgcolor=blue><marquee><font color=yellow>$

An = a+(n-1)d

A1 = 4+(1-1)(-3) = 4

A2 = 4+(2-1)(-3) = 1

A3 = 4+(3-1)(-3) = 4-6 = -2

A4 = 4+(4-1)(-3) = 4-9 = -5

Answered by Anonymous

First term = a = 4

Common difference = d = -3

No of terms = n = 4

thus,

the nth term, an = a+ (n-1)d

=> 4 + (n-1) -3

=> 4 -3n +3

=> 7 -3n

the fourth term = a4

=>7 - 3(4)

=> 7 -12

=>-5

the third term = a3

=>7 -3(3)

=>7 -9

=> -2

the 2nd term = a2

=> 7 - 3(2)

=>7 -6

=> 1

the first term = a

=> 4

thus, the first 4 terms are:

4, 1, -2, -5

Alternative method:

first term = a

=> 4

second term = a+d

=> 4 -3

=> 1

third term = a+2d

=> 4 -6

=> -2

fourth term = a+ 3d

=> 4- 9

=> -5

Previous Question

Next Question

Write first four terms of the AP, when the first term a and the common difference d are given as follows (iii) a = 4, d = – 3

Answers

Write first four terms of the AP, when the first term a and the common difference d are
given as follows
(iii) a = 4, d = – 3