Question

write first four terms of the AP when the first term a and the common difference D are the following a=_2 d=0​

Answer 1

Answer:

2, 2, 2, 2

Step-by-step explanation:

Given that,

a=2

d=0

we know that,

Tn = a + (n - 1) d

Here n = 1

T1 = 2 + ( 1 - 1) (0)

= 2 + (0)(0)

= 2 + 0

= 2

T2 = 2 + ( 2 - 1) (0)

= 2 + (1)(0)

= 2 + (0)

= 2

T3 = 2 + ( 3 - 1)(0)

= 2 + (2)(0)

= 2 + 0

= 2

T4 = 2 + ( 4 - 1)(0)

= 2 + (3)(0)

= 2 + 0

= 2

Therefore, the first four terms of AP are 2, 2, 2, 2.

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