Math, asked by nshankar852, 4 months ago

write five different linear eqtions in two variables and find three solutions for each of them​

Answers

Answered by itzsmartsilentkiller
1

Answ

Step-by-step explanation:

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Answered by XxxShivuuxxX
9

ANSWER

(i) x+y=10

(i) x+y=10(a) for x=1

(i) x+y=10(a) for x=11+y=10

(i) x+y=10(a) for x=11+y=10y=9

(b) for x=2

(b) for x=22+y=10

(b) for x=22+y=10y=8

(c) for x=3

(c) for x=33+y=10

(c) for x=33+y=10y=7

(c) for x=33+y=10y=7(ii) 2x+y=15

(c) for x=33+y=10y=7(ii) 2x+y=15(a) for x=1

(c) for x=33+y=10y=7(ii) 2x+y=15(a) for x=12×1+y=15

(c) for x=33+y=10y=7(ii) 2x+y=15(a) for x=12×1+y=15y=15−2=13

(b) for x=2

(b) for x=22×2+y=15

(b) for x=22×2+y=15y=15−4=11

(c) for x=3

(c) for x=32×3+y=15

(c) for x=32×3+y=15(iii) 2x−y=0

(c) for x=32×3+y=15(iii) 2x−y=0(a) for x=1

(c) for x=32×3+y=15(iii) 2x−y=0(a) for x=12×1−y=0

(c) for x=32×3+y=15(iii) 2x−y=0(a) for x=12×1−y=0y=2

(b) for x=2

(b) for x=22×2−y=0

(b) for x=22×2−y=0y=4

(c) for x=3

(c) for x=32×3−y=0

(c) for x=32×3−y=0y=6

(c) for x=32×3−y=0y=6(iv) 2x−y=1

(c) for x=32×3−y=0y=6(iv) 2x−y=1(a) for x=1

(c) for x=32×3−y=0y=6(iv) 2x−y=1(a) for x=12×1−y=1

(c) for x=32×3−y=0y=6(iv) 2x−y=1(a) for x=12×1−y=1y=2−1=1

(b) for x=2

(b) for x=22×2−y=1

(b) for x=22×2−y=1y=4−1=3

(c) for x=3

(c) for x=32×3−y=1

(c) for x=32×3−y=1y=6−1=5

(c) for x=32×3−y=1y=6−1=5(v) 2x+3y=0

(c) for x=32×3−y=1y=6−1=5(v) 2x+3y=0(a) for x=1

(c) for x=32×3−y=1y=6−1=5(v) 2x+3y=0(a) for x=12×1+3y=0

(c) for x=32×3−y=1y=6−1=5(v) 2x+3y=0(a) for x=12×1+3y=0y=−2/3

(b) for x=2

(b) for x=2 2×2+3y=0

(b) for x=2 2×2+3y=0y=−4/3

(c) for x=3

(c) for x=32×3+3y=0

(c) for x=32×3+3y=0y=−6/3=−2

hope it helps you ❤️

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