Math, asked by machindra1184, 9 months ago

write five numbers keeping the smallest of 49351 in the units place​

Answers

Answered by vaishnavi17858
1

Answer:

95341,43591,54391,39451,94351

Answered by jaseenanoufal2022sl
0

Answer:

The five numbers obtained by keeping the smallest of 49351 in the units place are 93451, 59431, 39541, 49531, 34951.

Step-by-step explanation:

Given : A number 49351 .

To find : we need to find 5 numbers keeping the smallest of 49351 in the units place.

Solution  : Here, the smallest of the given number 49351 is 1.

We need to place this 1 in the units place of a newly formed five numbers. We can form many numbers by keeping 1 in the units place by rearranging them. Also other numbers can be used to form numbers with 1 in the units place.

Here, we use the given digits as follows.

93451, 59431, 39541, 45391, 34951,49351, 365291,382651, ......

any five numbers can be found from the given numbers by placing 1 in the units place.

Therefore , five numbers obtained by keeping the smallest of 49351 in the units place are 93451, 59431, 39541, 49531,34951.

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