Question

write five pair of integers x and y such that x÷y=-3, one such pair in (6,-2) because 6÷(-2)=3.​

Answer 1

Answer:

Step-by-step explanation:6×  

2

−1

​

  =−3

(12, -4)

12\times\frac{-1}{4\ }\ \ =\ -3\12×  

4  

−1

​

  = −3  

(9,-3)

9\times\ \frac{-1}{3}\ \ =\ -3\9×  

3

−1

​

  = −3  

(15, -5)

15\times\frac{-1}{5}\ =\ -315×  

5

−1

​

 = −3

(18, -6)

18\times\frac{-1}{6}\ \ =-318×  

6

−1

​

  =−3