Question

write five pairs of integers (a,b) such that a÷b=-3.one such pair is (6,-3) because 6 ÷(-2)=(-3)

Answer 1

(12, -4) , (18, -6) , (24, -8), (30, -10)

Answer 2

Answer:$(3,-1),\ (-3,1),\ (-6,2),\ (6,-2),\ (-12,4)$

Step-by-step explanation:

The five pairs of integers $(a,b)$ such that$a\div b=-3$ are given below:-

.

$(3,-1)\text{ such that } 3\div-1=-3\\\\ (-3,1)\text{ such that } -3\div1=-3\\\\ (-6,2)\text{ such that } -6\div2=-3\\\\ (6,-2)\text{ such that } 6\div-2=-3\\\\ (-12,4)\text{ such that } -12\div4=-3$

Hence, the pairs of integers $(a,b)$ such that$a\div b=-3$ =$(3,-1),\ (-3,1),\ (-6,2),\ (6,-2),\ (-12,4)$