Write five pairs of integers (a,b) such that a÷b=-3 one such pair is (.-6,2)
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Answered by
15
(-9,3);(-12,4);(-15,5);(-18,6);(-21,7)
anakin1:
(a) multiplied by -3
still i didn't got
take any number as A for ex.5. then multiply the no.(A) by -3 , for ex. 5×-3=-15,this no will be B
take any number as A for ex.5. then multiply the no.(A) by -3 , for ex. 5×-3=-15,this no will be B
take any number as A for ex.5. then multiply the no.(A) by -3 , for ex. 5×-3=-15,this no will be B
take any number as A for ex.5. then multiply the no.(A) by -3 , for ex. 5×-3=-15,this no will be B
take any number as A for ex.5. then multiply the no.(A) by -3 , for ex. 5×-3=-15,this no will be B
take any number as A for ex.5. then multiply the no.(A) by -3 , for ex. 5×-3=-15,this no will be B
i am sorry I posted so many times , connection problem
ok no problem thanks a lot
Answered by
12
We can that by putting random values for a.
Let a=1
Given:
a/b = -3
1/b = -3
-3b = 1
b = 1/-3 = -1/3
You can find as many solutions as you want...
Let a=1
Given:
a/b = -3
1/b = -3
-3b = 1
b = 1/-3 = -1/3
You can find as many solutions as you want...
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