Question

write four arithmetic sequence with 100 as there sum of the first four terms?​

Answer 1

Answer:

here is 2 answer..

ihope u understand

Step-by-step explanation:

first is :

s4=22+24+26+28=100

Another solution are:

You’re trying to solve 4a + 6d = 100 (or 2a + 3d = 50), where a is the first number in the sequence and d is the difference. This is because that sequence is a + (a + d) + (a + 2d) + (a +3d) = 4a + 6d.

Clearly d must be even, so start with d = 2. Then a = (50 - 6)/2 = 22.

When d = 4, 6, and 8, a = 19, 16, and 13.

This gives four arithmetic sequences that sum to 100.

22, 24, 26, 28

19, 23, 27, 31

16, 22, 28, 34

13, 21, 29, 37

It should now be pretty clear that there are four more consisting of positive integers, with the last being

1, 17, 33, 49