Question

Write four rational numbers between −1 / 7 and 2 / 3

Answer 1

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Answer 2

Answer:

Four rational numbers between −1 / 7 and 2 / 3 are $( - \frac{2}{21} ),( \frac{1}{21} ),( \frac{5}{21} ),( \frac{10}{21} )$

Step-by-step explanation:

Here given two fractions are $- \frac{1}{7}$ and $\frac{2}{3}$

We want to find four rational number between given two rational numbers.

But question is what is rational number?

Any number that can be written as a fraction of two integers is called a rational number.

Here first we need to make denominator same of both fraction.

First we are taking the fraction $- \frac{1}{7}$

We are multiplying denominator and numerator by 3,

$- \frac{1 \times 3}{7 \times 3} = - \frac{3}{21}$

Then we are taking the fraction $\frac{2}{3}$

We are multiplying denominator and numerator by 7,

$\frac{2 \times 7}{3 \times 7} = \frac{14}{21}$

Now, four rational numbers between

$- \frac{3}{21}$and $\frac{14}{21}$ are $( - \frac{2}{21} ),( \frac{1}{21} ),( \frac{5}{21} ),( \frac{10}{21} )$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549