Question

write four solution for each of the following equation i) 2 X + y is equal to 7​

Answer 1

QUESTION:-

✯.ᴡʀɪᴛᴇ ғᴏᴜʀ sᴏʟᴜᴛɪᴏɴ ғᴏʀ ᴇᴀᴄʜ ᴏғ ᴛʜᴇ ғᴏʟʟᴏᴡɪɴɢ ᴇϙᴜᴀᴛɪᴏɴ ɪ) 2 x + ʏ ɪs ᴇϙᴜᴀʟ ᴛᴏ 7

ANSWER✔

$\Large\underline\bold{GIVEN,}$

$\sf\dashrightarrow equation, 2x+y=7$

$\Large\underline\bold{TO\:FIND,}$

$\sf\dashrightarrow find\:any\:four\:solutions\:for\:the\:given\:equation$

$\Large\underline\bold{SOLUTION,}$

$\sf\therefore TAKING\:x\:=0$

THEN,

$\sf\therefore 2x+y=7$

$\sf\implies 2 \times (0) +y=7$

$\sf\implies 0+y=7$

$\sf\implies y=7$

$\sf{\boxed{\sf{(x_1,y_1)=(0,7)}}}$

$\sf\therefore TAKING\:x\:=1$

THEN,

$\sf\therefore 2x+y=7$

$\sf\implies 2 \times (1) +y=7$

$\sf\implies 2+y=7$

$\sf\implies y=7-2$

$\sf\implies y=5$

$\sf{\boxed{\sf{(x_2,y_2)=(1,5)}}}$

$\sf\therefore TAKING\:x\:=2$

THEN,

$\sf\therefore 2x+y=7$

$\sf\implies 2 \times (2) +y=7$

$\sf\implies 4+y=7$

$\sf\implies y=7-4$

$\sf\implies y=3$

$\sf{\boxed{\sf{(x_3,y_3)=(2,3)}}}$

$\sf\therefore TAKING\:x\:=6$

THEN,

$\sf\therefore 2x+y=7$

$\sf\implies 2 \times (6) +y=7$

$\sf\implies 12+y=7$

$\sf\implies y=7-12$

$\sf\implies y=-5$

$\sf{\boxed{\sf{(x_4,y_4)=(6,-5)}}}$

THEREFORE,

$\sf\therefore THE\:REQUIRED\:SOLUTIONS\:ARE,$

$\sf\therefore (x_1,y_1)=(0,7)$

$\sf\therefore (x_2,y_2)=(1,5)$

$\sf\therefore (x_3,y_3)=(2,3)$

$\sf\therefore (x_4,y_4)=(6,-5)$

________________________

Answer 2

Answer:

2x+y=7 2 x + y = 7 are (0,7), (1,5), (2,3), (3,1). Hence, four solutions for equation x=4y x = 4 y are (0, 0), (1, 4), (-4,-1), (8, 2).