Question

write four solution of linear equation x - 3y = 2 please.......... solve the questions​

Answer 1

Answer:

The given equation is 2x+3y=6.

When, x=0,y=2

When, y=0,x=3

when, x=1, y=4/3

when y=1, x=3/2

Answer 2

Answer:

Four solutions of the equations x - 3y = 2 are

x = 0 and y =- $\frac{2}{3}$

x = 1 and y = $\frac{-1}{3}$

x = 2 and y = 0

x = 3 and y = $\frac{1}{3}$

Step-by-step explanation:

Given equation is

x - 3y = 2

To find

Four solutions to this linear equation

Solution:

The given equation is a linear equation

We know that a linear equation represents a straight line.

Hence, every point in this line is a solution to this equation.

∴ There is infinitely many solutions to this equation x - 3y = 2

In order find solution to this equation,

if x = 0,

x - 3y = 2 ⇒0-3y = 2

⇒-3y = 2

⇒y = - $\frac{2}{3}$

x = 0 and y = -$\frac{2}{3}$ is a solution of this equation

Again if x =1

x - 3y = 2 ⇒1-3y = 2

⇒-3y = 2-1 = 1

⇒y = $\frac{-1}{3}$

x = 1 and y = $\frac{-1}{3}$  is a solution of this equation

Again if x =2

x - 3y = 2 ⇒2-3y = 2

⇒-3y = 2-2 = 0

⇒y = 0

x = 2 and y = 0 is a solution of this equation

Again if x =3

x - 3y = 2 ⇒3-3y = 2

⇒-3y = 2-3 = -1

⇒y = $\frac{1}{3}$

x = 3 and y = $\frac{1}{3}$ is a solution of this equation

Hence, four solutions of the equations x - 3y = 2 are

x = 0 and y =- $\frac{2}{3}$

x = 1 and y = $\frac{-1}{3}$

x = 2 and y = 0

x = 3 and y = $\frac{1}{3}$

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