Question

Write four solution of the equation 2x + 3y + 4 = 0

Answer 1

2x+3y+4=0

Solve for x

$2x+4= -3y \\ </p><p>2x = -3y-4 \\ </p><p> x = -3y-4÷2$

To, Simplify

$- 3y - \frac{4}{2} \\ - 3y - 2$

Solve for y

$3y + 4 = - 2x \\ 3y = - 2x - 4 \\ y = - 2x - 4 \div 3 \\ y - 2(x + 2) \\ y = - 2(x + 2) \div 3$

To, Simplify

$y = - 2(x + 2) \div 3 \\ y \times 3 = - 2(x + 2) \\ 3y = - 2(x + 2) \\ - \frac{3y}{2} - 2 = x \\ x = - \frac{3y}{2} - 2$

Domain of

$y = - 2(x + 2) \div 3 \\ x∈R</p><p></p><p></p><p>$

Range of

$x - \frac{3y}{2} - 2 \\ y∈R</p><p></p><p></p><p>$

Asymtopes

1. Vertical Asymtopes None

2. Horizontal Asymtopes

$- 2x \times x + 2 \div 3≈ - 2(x + 2) \div 3 \\ - 2(x + 2) \div 3 = - 2(x + 2) \div 3 \\ y = - 2(x + 2) \div 3$

3. Slat Asymtopes None