Question

write four solutions for each of the following equation :- (1) 4x+2y=14 (2) 8/4x=8y​

Answer 1

Answer:

(i) (1,5, (2,3), (3,1) and (4,-1)...

Hope you will do for (ii)!!

Step-by-step explanation:

Given,

4x + 2y = 14...(i)

8/4x = 8y...(ii)

$For \: Eq. (i), \\ 4x + 2y = 14 \\ = 2y = 14 - 4x \\ y = \frac{14 - 4x}{2} \\ let \: x = 1 \\ y = \frac{14 - 4(1)}{2} \\ = \frac{14 - 4}{2} \\ = \frac{10}{2} \\ = 5 \\ let \: x = 2 \\ y = \frac{14 - 4(2)}{2} \\ = \frac{14 - 8}{2} \\ = \frac{6}{2} \\ = 3 \\ let \: x = 3 \\ y = \frac{14 - 4(3)}{2} \\ = \frac{14 - 12}{2} \\ \frac{2}{2} \\ = 1 \\ let \: x = 4 \\ y = \frac{14 - 4(4)}{2} \\ = \frac{14 - 16}{2} \\ = \frac{ - 2}{2} \\ = - 1 \\ solutions \: for \: eq \: (i) \: are \: (1, 5), \: (2, 3), \: (3, 1) \: and \: (4, - 1). \\ same \: you \: can \: do \: it \: for \: eq. \: (ii)$

Hope this will help you!!

Hope tou will try to make Solutions for Eq. (ii)!!