Question

write four solutions for each of the following equation: 3x+4y-24=0​
please answer this correctly
it's very urgent and important

Answer 1

Answer:

Step-by-step explanation:

Rearrrange the equation

3x + 4y = 24

x = 0

Then 0 + 4y = 24

y = 6

so x = 0, y = 6 (i)

y = 0

then

3x + 0 = 24

x = 8

so, y = 0, x = 8

x = 4 then

12 + 4y = 24

y = 3

so, x = 4, y = 3

x = 12

36 + 4y = 24

4y = -12

y = -3

so, x = 12, y = -3

Hope it helped

Answer 2

Answer:

Given that:

3x+4y−24=0

Its x-intercept =(8,0)

and its y-intercept =(0,6)

Since, AOB is a right angled triangle.

So, mid-point of the hypotenuse is the circumcentre.

$( \frac{8 + 0}{2} and \frac{0 + 6}{2} ) = (4and3)$

Hence, circumcentre=(4,3)