Question

write four solutions for each of the following solution. 1) 2x+y=7. 2) πx+y=9​

Answer 1

Answer:

(i) 2x+y=7

y=7–2x

When x=0, then

y=7–2×0

y=7–0

y=7

When x=1 then

y=7–2×1

y=7–2

y=5

When x=2 then

y=7–2×2

y=7−4

y=3

When x=3 then

y=7−2×3

y=7−6

y=1

Hence, four solutions for equation 2x+y=7 are (0,7),(1,5),(2,3),(3,1).

(ii) πx+y=9

y=9−πx

When x=−1 then

y=9−π×−1

y=9+π

When x=0 then

y=9−π×0

y=9

When x=1 then

y=9−π×1

y=9−π

When x=2 then

y=9−π×2

y=9−2π

Hence, four solution for equation πx+y=9 are (−1,9+π),(0,9),(1,9−π),(2,9−2π).

(iii) x=4y

When y=0, then

x=4×0

x=0

When y=1 then

x=4×1

x=4

When y=−1 then

x=4×−1

x=−4

When y=2 then

x=4×2

x=8

Hence, four solutions for equation x=4y are (0,0),(4,1),(−4,−1),(8,2).

The provided answer is one of the various possible solutions. This question might have other solution too.