Question

write four solutions of 2x+4y=7

Answer 1

SOLUTION :-

For equation 2x +4y = 7

Here,

=> 2x + 4y = 7

=> 4y = 7 - 2x

$= > \: y = \frac{7 - 2x}{4}$

$\small{\sf → For \: first...}$

putting x = 0

Then,

$= > \: y = \frac{7 - 0}{4}$

$= > \: \underline{y = \frac{7}{4} }$

$\small{\sf → For \: Second...}$

putting x = 1

Then,

$= > \: y = \frac{7 - 2}{4}$

$= > \: \underline{ y = \frac{5}{4} }$

$\small{\sf → For \: Third...}$

putting x = 2

Then,

$= > \: y = \frac{7 - 4}{4}$

$= > \: \underline{y = \frac{3}{4} }$

$\small{\sf → For \: Fourth...}$

putting x = 3

Then,

$= > \: y = \frac{7 - 6}{4}$

$= > \: \underline{y = \frac{1}{4} }$

Which are the required solutions.

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