Question

write four solutions of the linear equation 4x-3y+12=0.

Answer 1

See the image .... Hope this helps................

Answer 2

Hi ☺☺
_______________
4x-3y+12 = 0

=> 4x-3y = -12
_______________
Put x = 0

4(0)-3y = -12

=> 3y= 12 => y = 4 ___(0,4)
_______________
put y = 0

4x-3(0) = -12

=> 4x = -12 => x = -3 ___(-3,0)
_______________
put x = 1

4(1)-3y = -12

=> -3y = -16 => y = 16/3 __(1,16/3)
________________
put y = 1

4x-3(1) = -12

=> 4x = -9 => x = -9/4 __(9/4,1)
________________
☺☺