Question

write gives of 5 natural number which are multiples of 3 and verify the following the cube of a natural number which is a multiple of 3 is a multiple of 27

Answer 1

(3)^3 = 27
(6)^3 = 216
9^3 = 729
12^3 = 1728
15^3 = 3375
this is question of s chand math book class 8th
ex 4

Answer 2

Answer:

Let say 5 multiples of 3 = 6 , 9 , 12 , 15 , 21

Cube of multiple of 3 are as follows :

6³ = 216

9³ = 729

12³ = 1728

15³ = 3375

21³ = 9261

Now we have to verify cube of multiple of 3 is also multiple of 3

so we check above mentioned cubes are multiple of 3 or not.

If those nos. divided by 3 then they are multiple of 3

216 ÷ 3 = 72 gives 216 is multiples of 3

729 ÷ 3 = 243 gives 729 is multiples of 3

1728 ÷ 3 = 576 gives 1728 is multiples of 3

3375 ÷ 3 = 1125 gives 3375 is multiples of 3

9261 ÷ 3 = 3087 gives 9261 is multiples of 3

Hence verified