Question

write how to find area and perimeter in triangle,square,rectangle

Answer 1

$\mathfrak{dear\;user}$

$\mathfrak{question-to\: find \:area \:,\:perimeter \:of \:square\:,\:triangle \:and \:rectangle}$

$\mathfrak{here\:is\:the\:solution}$

$\mathbb{ANSWER}$

$\mathbf {triangle }$

$\textsf{Area-1/2 x base x height }$

$\textsf{Area-A,Height-,Base-B}$

$\textsf{A=1/2 x B x H}$

$\textsf{Perimeter-a+b+c}$

$\textsf{Perimeter-,1st side-A,2nd side-B, 3rd side-C}$

$\textsf{P=A+B+C}$

$\mathbf{square}$

$\textsf{A-S x S}$

$\textsf{Area-A,Side-S}$

$\textsf {A=S x S }$

$\textsf{perimeter-4s }$

$\textsf{Perimeter-P,Side-S}$

$\textsf{P=4S }$

$\mathbf{rectangle}$

$\textsf{Area-L x B}$

$\textsf{Area-A,Length-L,Breadth-B}$

$\textsf{A-L x B}$

$\textsf{perimter-sum of all sides}$

$\textsf{P=2(l+b)}$

$\textsf{Perimeter-P,Length-L,Breadth-B}$

$\textsf{P=2l+2b}$

$\textsf{P=2(l+b)}$

$\mathbb{EXTRA\:INFORMATION}$

$\mathbf{TRIANGLE}$

$\textsf {A triangle is a polygon with three edges and three vertices.}$

$\textsf{Area: 1/2 x base x height }$

$\textsf{Perimeter: sum of side lengths of the triangle}$

$\textsf{Number of vertices: 3}$

$\textsf{Number of edges: 3}$

$\textsf{Sum of interior angles: 180}$

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(2.85,3.2){ \bf A }\put(0.5,-0.3){ \bf C }\put(5.2,-0.3){ \bf B }\end{picture}$

$\mathbf{SQUARE}$

$\textsf{a square is a regular quadrilateral, which means that it has four equal sides and four equal angles}$

$\textsf{A rectangle with two adjacent equal sides}$

$\textsf{A rhombus with a right vertex angle}$

$\textsf {A rhombus with all angles equal}$

$\textsf{A parallelogram with one right vertex angle and two adjacent equal sides}$

$\textsf{A quadrilateral with four equal sides and four right angles}$

$\textsf{The diagonals of a square bisect its angles.}$

$\textsf{Opposite sides of a square are both parallel and equal in length.}$

$\textsf{All four sides of a square are equal.}$

$\textsf {The diagonals of a square are equal.}$

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(4,0){2}{\line(0,1){4}}\multiput(0,0)(0,4){2}{\line(1,0){4}}\put(-0.5,-0.5){\bf D}\put(-0.5,4.2){\bf A}\put(4.2,-0.5){\bf C}\put(4.2,4.2){\bf B}\put(1.5,-0.6){\bf\large x\ cm}\put(4.4,2){\bf\large x\ cm}\end{picture}$

$\mathbf{RECTANGLE}$

$\textsf{ a rectangle is a quadrilateral with four right angles}$

$\textsf{a parallelogram with at least one right angle}$

$\textsf{a parallelogram with diagonals of equal length}$

$\textsf{a parallelogram ABCD where triangles ABD and DCA are congruent}$

$\textsf{an equiangular quadrilateral}$

$\textsf{a quadrilateral with four right angles }$

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large x cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large y cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

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Answer 2

Answer:

The answer

Area of triangle = 1/2 × base × height

Perimeter of triangle = a +b+c

Area of square = side ×side

perimeter of square = 4 side (4s)

Area of rectangle = Length × Breath

perimeter of rectangle = 2( length × breath )

$hope \: this \: helps \: you$