Math, asked by ritviksingh11, 8 months ago

write i (2+3i)(3+2i)/5+i into

a+ib​

Answers

Answered by sehejarora75
0

Answer:

2−3i)

​  

 

Multiplying both numerator and denominator by the Complex conjugate of the denominator

Therefore,

(3+4i)

(2−3i)

​  

=  

3+4i

2−3i

​  

×  

3−4i

3−4i

​  

 

=  

(3)  

2

−(4i)  

2

 

(2−3i)(3−4i)

​  

 

=  

9+16

(6+12i  

2

)−(9+8)i

​  

 

=  

25

−6−17i

​  

 

=  

25

−6

​  

+  

25

−17

​  

i

Here, A=  

25

−6

​  

 and B=  

25

−17

​  

 

Step-by-step explanation:

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