write i (2+3i)(3+2i)/5+i into
a+ib
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Answer:
2−3i)
Multiplying both numerator and denominator by the Complex conjugate of the denominator
Therefore,
(3+4i)
(2−3i)
=
3+4i
2−3i
×
3−4i
3−4i
=
(3)
2
−(4i)
2
(2−3i)(3−4i)
=
9+16
(6+12i
2
)−(9+8)i
=
25
−6−17i
=
25
−6
+
25
−17
i
Here, A=
25
−6
and B=
25
−17
Step-by-step explanation:
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