Question

Write i) 64 = 82 ii) 64 = 43 in logarithmic form.

Answer 1

Hey there!

The logarithmic form of x^n = a is
$log_{x}(a) = n$
where x, a are positive integers.

So, Given,

i) 64 = 8²

Here n = 2 , a = 64 , x = 8

So, logarithmic form of 64 = 8² is
$log_{8}(64) = 2$

ii) 64 = 4³

Here n = 3 , a = 64 , x = 4

So, Logarithmic form of 64 = 4³ is
$log_{4}(64) = 3$

Hope helped!

Answer 2

Answer:

log 64 ( base 8 ) = 2

log 64 ( base 4 ) = 3

Step-by-step explanation:

**********************************

We know that ,

If aⁿ = x , then log x( base a ) = n

Where a and x are positive

numbers and a ≠ 1

************************************

Here ,

i )64 = 8²

=> log 64 ( base 8 ) = 2

ii ) 64 = 4³

=> log 64 ( base 4 ) = 3

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