Question

Write ideal gas equation for 32 gm oxygen gas.​

Answer 1

Answer:

The answer is PV = RT/4

Explanation:

The atomic mass of oxygen is 32 which is equal to 1 mole of oxygen.

Therefore, 32g 02 means 1 mole of oxygen and 8g means that oxygan has quarter moles. That means no. of moles n = 1/4 moles

According to ideal gas equation

PV = nRT

Here n = 1/4 moles

So,

PV = 1/4RT

Or

PV = RT/4

Answer 2

Given - Mass of oxygen gas : 32 gram

Find - Ideal gas equation for given gas

Solution - Ideal gas equation is the equation written as follows -

PV = nRT. In this formula, P is pressure, V is volume, n is number of moles, R is gas constant and T is temperature.

So, calculating number of moles for given mass of oxygen.

Number of moles = mass/molar mass

Number of moles = 32/32

Number of moles = 1

Now keeping the value of number of moles in ideal gas equation.

P*V = 1*R*T

So, ideal gas equation for 32 gram of oxygen gas is PV = RT.