Question

write ideal gas equation for mass of 8 g of oxygen gas​

Answer 1

Answer:

The answer is PV = RT / 4

Explanation:

The atomic mass of oxygen is 32 which is equal to 1 mole of oxygen.

Therefore, 32g O2 means 1 mole of oxygen and 8g means that oxygan has quarter moles. That means no. of moles n = 1/4 moles

According to ideal gas equation

PV = nRT

Here n = 1/4 moles

So,

PV = 1/4RT

Or

PV = RT / 4

Please follow me

Answer 2

PV= RT/4

Explanation:

From ideal gas equation,

PV = nRT

n=mass/molecular weight

For o₂, molecular weight=32g

mass=8g

n=8/32=1/4

PV=RT/4

HENCE, PV=RT/4is the realation.