Question

Write If x = 6 is a zero of the polynomial 2x^2 + kx -12, then find the value of k





( ╹▽╹ )​

Answer 1

Answer:

$2x {}^{2} + kx - 12 \\ 2 ({6})^{2} + k6 - 12 \\ 2(12) + k6 - 12 \\ 24 + k6 - 12 \\ k6 = 12 - 24 \\ k6 = - 12 \\ k = \frac{6}{ - 12}$

$k = - 2$

Step-by-step explanation:

hope you appreciate this ans

Answer 2

Answer:

K= -10

Step-by-step explanation:

IF X= 6,

PUT THE VALUE OF X IN GIVEN POLYNOMIAL,

i.e. 2X²+KX-12 = 0

=>. 2(6)²+K(6)-12= 0

=>. 2(36)+6K-12= 0

=>. 72+6K-12= 0

=>. 60+6K= 0

=>. 6K= -60

=>. K= -60/6

=>. K= -10