Question

write in descending order 7/12,4/6,1/3,5/24​

Answer 1

Answer:

The fraction in descending order are in the following sequence:

$\bf{\dfrac{4}{6},\dfrac{7}{12},\dfrac{1}{3},\dfrac{5}{24}}$

Step-by-step explanation:

What to do?

Write the following in descending order:

$\sf{\longmapsto\dfrac{7}{12},\dfrac{4}{6},\dfrac{1}{3},\dfrac{5}{24}}$

Process:

To write the fractions in descending order, we first have to convert each fraction to like fractions with same denominator. After converting the fractions, we have to compare the fractions as per their value. The fraction having the highest numerator has the highest value. After that, we have to arrange the fractions in descending order.

Solution:

Calculating LCM of 12, 6, 3 and 24:

$\large{\begin{array}{c|c}\underline{3}&\underline{\;12,6,3,24\;}\\\underline{2}&\underline{\;\;\;4,2,1,8\;\;\;}\\\underline{2}&\underline{\;\;\;2,1,1,4\;\;\;}\\&{1,1,1,2}\end{array}}$

Hence, the LCM of 12, 6, 3 and 24 = 3 × 2 × 2 × 2 = 24.

Converting each fraction into like fractions with denominator 24:

$\sf{\longmapsto\dfrac{7}{12}=\dfrac{7\times2}{12\times2}=\dfrac{14}{24}}$

$\sf{\longmapsto\dfrac{4}{6}=\dfrac{4\times4}{6\times4}=\dfrac{16}{24}}$

$\sf{\longmapsto\dfrac{1}{3}=\dfrac{1\times8}{3\times8}=\dfrac{8}{24}}$

$\sf{\longmapsto\dfrac{5}{24}=\dfrac{5\times1}{24\times1}=\dfrac{5}{24}}$

Clearly,

$\sf{\dfrac{16}{24}>\dfrac{14}{24}>\dfrac{8}{24}>\dfrac{5}{24}}$

Therefore,

$\sf{\dfrac{4}{6}>\dfrac{7}{12}>\dfrac{1}{3}>\dfrac{5}{24}}$