Question

Write in expanded form (1/3x-2/3y)^3

Answer 1

Answer:

(a-b) ³= a³-b³- 3ab(a-b)

= (1/3x-2/3y)³= (1/3x)³ -(2/3y)³ -3(1/3x)(2/3y)(1/3x-2/3y)

= 1³/3³x³ - 2³/3³y³ -2/3xy(1/3x-2/3y)

= 1/27x³ - 8/27y³ -2/9x²y + 4/9xy²

$<marquee>$

$\mathfrak{follow \: me}$

Answer 2

(1/3x-2/3y)^3

(a-b)(a^2 + b^2 +ab)

=1^3/(3x)^3-2^3/(3y)^3

=1/27x^3-8/27y^3

=y^3-8x^3/27x^3y^3Answer