Question

Write in expanded form :-(x + 3y)3​

Answer 1

ANSWER : x3 + 9y3 + 9x2y + 27xy2

Step-by-step explanation:

(a + b)3 = a3 + b3 +3a2b + 3ab2

so,

(x)3 + (3y)3 + 3 x2 3y + 3 x 3y2

=x3 + 9y3 + 9x2y + 27xy2

Answer 2

Answer:

$(x+3y)^{3} = x^{3}+ 27y^{3}+ 9x^{2} y + 27xy^{2}$ is its required expanded form.

Step-by-step explanation:

• To find:

Expanded form of -  $(x+3y)^{3}$

• Formula used:

      Expanding using cubic identity,

           $(a+b)^{3} = a^{3}+ b^{3}+ 3ab(a+b )$

or

       $(a+b)^{3} = a^{3}+ b^{3}+3a^{2} b+3ab^{2}$

• Here $a = x$ and $b= 3y$

-      $(x+3y)^{3} = x^{3}+ 27y^{3}+ 9xy(x+3y )$

we know that, cube of $3$ is $27$.

• $3^{3} = 3*3*3 = 27$

$(x+3y)^{3} = x^{3}+ 27y^{3}+ 9x^{2} y + 27xy^{2}$

Therefore, the final answer is $(x+3y)^{3} = x^{3}+ 27y^{3}+ 9x^{2} y + 27xy^{2}$.

#SPJ2